Question

Tentukan jumlah setiap deret geometri dibawah ini

1/4+1/8+1/16+...... (hingga suku ke 7)

Answer 1

1/4+1/8+1/16+1/32+1/64+1/128+1/256
2. 2. 2. 2. 2. 2. 2
maaf kalau salah

Answer 2

Geometri

1/4,1/8,1/16,...
r = 1/8/1/4 = 1/8×4/1 = 4/8 = 1/2

u4 = a×r^n-1
u4 = 1/4×1/2^4-1
u4 = 1/4×1/2³
u4 = 1/4×1/8
u4 = 1/32

u5 = a×r^n-1
u5 = 1/4×1/2^5-1
u5 = 1/4×1/2^4
u5 = 1/4×1/16
u5 = 1/64

u6 = a×r^n-1
u6 = 1/4×1/2^6-1
u6 = 1/4×1/2^5
u6 = 1/4×1/32
u6 = 1/128

u7 = a×r^n-1
u7 = 1/4×1/2^7-1
u7 = 1/4×1/2^6
u7 = 1/4×1/64
u7= 1/256

1/4,1/8,1/16,1/32,1/64,1/128,1/256