16^X+64=20*2^X
LOG(16^X+64)=LOG(20*2^X)
log(16^x)+log64=20log(2^x)
xlog(16)+log64=20xlog(2)
xlog(16)-20xlog(2)=-log64
x(log16-20log2)=-log64
x=(-log64)/(log16-20log2)
x=3/8
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
16^X+64=20*2^X
LOG(16^X+64)=LOG(20*2^X)
log(16^x)+log64=20log(2^x)
xlog(16)+log64=20xlog(2)
xlog(16)-20xlog(2)=-log64
x(log16-20log2)=-log64
x=(-log64)/(log16-20log2)
x=3/8