PROCEDIMIENTO:
[tex]15t - 20 = 6t - (2t+ 2) + (- 5t + 3)\\15t-20=6t-2t-2-5t+3\\15t-20=-t-1\\15t+t=1+20\\16t=21\\\\t=\frac{21}{16}[/tex]
El valor de "t" es → [tex]\frac{21}{16}[/tex]
Atte: Sabius95
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PROCEDIMIENTO:
[tex]15t - 20 = 6t - (2t+ 2) + (- 5t + 3)\\15t-20=6t-2t-2-5t+3\\15t-20=-t-1\\15t+t=1+20\\16t=21\\\\t=\frac{21}{16}[/tex]
El valor de "t" es → [tex]\frac{21}{16}[/tex]
Atte: Sabius95