Jawaban:
• Jarak bayangan terhadap benda = - 2 cm
• Sifat bayangan = maya, tegak, dan diperkecil
Penjelasan:
• 1/f = 1/s + 1/s'
1/s' = - 1/f - 1/s
= - 1/6 - 1/3
= - 1/6 - 2/6
= - 3/6 = - 2/1 = - 2 cm
• M = s'/s
= - 2/4
= - 1/2 = 0,5 kali
Sifat bayangan: Maya, tegak, dan diperkecil
maaf kalau ada yang salah, semoga membantu^^
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Jawaban:
• Jarak bayangan terhadap benda = - 2 cm
• Sifat bayangan = maya, tegak, dan diperkecil
Penjelasan:
• 1/f = 1/s + 1/s'
1/s' = - 1/f - 1/s
= - 1/6 - 1/3
= - 1/6 - 2/6
= - 3/6 = - 2/1 = - 2 cm
• M = s'/s
= - 2/4
= - 1/2 = 0,5 kali
Sifat bayangan: Maya, tegak, dan diperkecil
maaf kalau ada yang salah, semoga membantu^^