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f(1)=4
f(3)=6
Rumus = f(x)=ax+b
(i)a(1)+b=4
a+b=4
(ii)a(3)+b=6
3a+b=6
Eliminasi (ii)-(i)
3a+b=6
a+b=4
2a=2
a=1
Substitusi
a+b=4
1+b=4
b=4-1
b=3
Masukkan a dan b
f(x)=ax+b
f(x)=x+3