15 gram urea CO(NH2)2 (Mr=60) dilarutkan dengan 400 gram etanol. jika Kb etanol = 1,19 dan titik didih etanol 78,4°C , tentukan titik didih larutan urea dalam etanol.
Tolong dibantu Cooy. Thanks ^_^
jasminezul
Molalitas urea= 15/60 x 1000/400 = 0.625 kb urea sesuai ketetapan = 0.52 ΔTb= molalitas x Kb urea = 0.625 x 0.52 = 0.325 Tburea= Tb pelarut - ΔTb = 78.4 - 0.325 = 78.075
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nenyshrlni
Delta Tb= molalitasx kb =gr/Mr x 1000/pelarut x 1,19 =15/60 x 1000/400 x 1,19 =0,625 x 1,19 =0,74
kb urea sesuai ketetapan = 0.52
ΔTb= molalitas x Kb urea
= 0.625 x 0.52
= 0.325
Tburea= Tb pelarut - ΔTb
= 78.4 - 0.325 = 78.075
=gr/Mr x 1000/pelarut x 1,19
=15/60 x 1000/400 x 1,19
=0,625 x 1,19
=0,74
Tb= Tb* + delta Tb
=100 + 0,74
= 100,74