Si se cumple que secβ = 17/15 determina el valor de tanβ AYUDAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA :(
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Explicación paso a paso:
[tex] \sec( \beta ) = \frac{17}{15} [/tex]
HIPOTENUSA:17
CA=15
x²=15²-17²
x²=64
x=8
CO=8
TAN(B)=CO/CA
Tan=8/15