Odpowiedź:
e)
[tex]\frac{\sqrt[3]{-16} }{5\sqrt[3]{2} } - \frac{\sqrt[3]{-72} }{\sqrt[3]{-9} } = \frac{\sqrt[3]{-8*2} }{5\sqrt[3]{2} } - \frac{\sqrt[3]{-9*8} }{\sqrt[3]{-9} }= \frac{-2\sqrt[3]{2} }{5\sqrt[3]{2} } -\frac{2\sqrt[3]{-9} }{\sqrt[3]{-9} } = \frac{-2}{5} -2=2\frac{2}{5}[/tex]
f)
[tex]\frac{\sqrt[5]{-4*32} }{\sqrt[5]{-4} } + \frac{\sqrt[7]{-128}}{\sqrt[9]{-1} } = \frac{2\sqrt[5]{-4} }{\sqrt[5]{-4} } +\frac{-2}{-1} = 2+2=4[/tex]
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Odpowiedź:
e)
[tex]\frac{\sqrt[3]{-16} }{5\sqrt[3]{2} } - \frac{\sqrt[3]{-72} }{\sqrt[3]{-9} } = \frac{\sqrt[3]{-8*2} }{5\sqrt[3]{2} } - \frac{\sqrt[3]{-9*8} }{\sqrt[3]{-9} }= \frac{-2\sqrt[3]{2} }{5\sqrt[3]{2} } -\frac{2\sqrt[3]{-9} }{\sqrt[3]{-9} } = \frac{-2}{5} -2=2\frac{2}{5}[/tex]
f)
[tex]\frac{\sqrt[5]{-4*32} }{\sqrt[5]{-4} } + \frac{\sqrt[7]{-128}}{\sqrt[9]{-1} } = \frac{2\sqrt[5]{-4} }{\sqrt[5]{-4} } +\frac{-2}{-1} = 2+2=4[/tex]