Question

Koordinat titik fokus elips x^2/9+y^2/13=1 adalah…

Ket tanda ^ adalah akar 2

Answer 1

Verified answer

Jawab

x²/ 9 +  y²/13 = 1 →  (x - p)²/b² + (y- q)²/a² = 1
p = 0, q= 0
b² = 9, a² = 13
c²= 13-9- 4
c = 2
Fokus  ( p , q +_ c)
Fokus 1 =  (0, 2)  
Fokus 2 = (0 , -2)