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Verified answer
Sin²a+cos²a=1cos²a=1-sin²a
cos²a=1-(5/13)²
cos²a=1-25/169
cos²a=169-25/169
cos²a=144/169
cosa= 12/13 kuadran 2 = -12/13
sin2a= 2sinacosa
sin2a=2(5/13)(-12/13) = -120/169
Verified answer
Jawabα di kuadran II , tumpul
sin α = 5/13 = y/r
y= 5, r = 13, x = 12
cos α = - x/r = - 12/13
sin 2α = 2 sin α cos α
sin 2α = 2(5/13)(- 12/13) = - 120/169