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12x² - 3x = 0
a = 12
b = - 3
c = 0
Formula.
x = [- b +/-√(b² - 4ac)]/2a
x = [ - (- 3) +/- √((- 3)² - 4(12)(0))]/2(12)
x = [ 3 +/-√(9 - 0)]/24
x = [3 +/- √9]/24
x = [3 +/- 3)/24
x₁ = [3 + 3]/24
x₁ = 6/24 Simplificas.
x₁ = 1/4
o
x₂ = [3 - 3]/24
x₂ = 0/24
x = 0
Solución.
(1/4 , 0)
a = 12
b = - 3
c = 0
La Formula.
x = [- b +/-√(b² - 4ac)]/2a
x = [ - (- 3) +/- √((- 3)² - 4(12)(0))]/2(12)
x = [ 3 +/-√(9 - 0)]/24
x = [3 +/- √9]/24
x = [3 +/- 3)/24
x₁ = [3 + 3]/24
x₁ = 6/24 Aquí Simplificas para saber..
x₁ = 1/4
o
x₂ = [3 - 3]/24
x₂ = 0/24
x = 0
La Solución es
(1/4 , 0)