Question

12t-2<-5t+36

8x-8<=-72

2cos^2(x)-sqrt(3)cos(x)=0, 0^{\circ}< x< 360^{\circ}

Answer 1

Respuesta:

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Explicación pasddddddddddddddddddo a paso:

Answer 2

Verified answer

Respuesta:

12t-2<-5t+36

[tex]12t-2+2<-5t+36+2\\\\12t<-5t+38\\\\12t+5t<-5t+38+5t\\\\17t<38\\\\\frac{17t}{17}<\frac{38}{17}\\\\t<\frac{38}{17}[/tex]

8x-8<=-72

[tex]8x-8+8\le \:-72+8\\\\8x\le \:-64\\\\\frac{8x}{8}\le \frac{-64}{8}\\\\x\le \:-8\\\\[/tex]

2cos^2(x)-sqrt(3)cos(x)=0, 0^{\circ}< x< 360^{\circ}

[tex]x=30^{\circ \:},\:x=330^{\circ \:},\:x=90^{\circ \:},\:x=270^{\circ \:}[/tex]