Tentukan nilai
A. Log5+Log200-Log10=.........
B. 0.5Log1/8+3Log27-5Log1/125=.....
A. Log5+Log200-Log10=.........
B. 0.5Log1/8+3Log27-5Log1/125=.....
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Verified answer
A.log5 + log200 - log 10 = log (5x200/10) = log 100 = log 10² = 2
b.
0,5log⅛ + ³log27 - 5log1/125
= ½log½³ + ³log3³ - 5log5-³
= 3 + 3 - 3
= 3