Explicación paso a paso:
La suma o resta de fracciones es una de las operaciones básicas que permite combinar dos o más fracciones
Resolvamos:
[tex]\frac{2}{3} - \frac{7}{15}=\frac{(2)(5) - (7)(1) }{15} =\frac{10-7}{15} =\frac{3}{15} =\frac{1}{5}[/tex]
[tex]\frac{4}{9} - \frac{1}{3}=\frac{(4)(1) - (1)(3) }{9} =\frac{4-3}{9} =\frac{1}{9}[/tex]
[tex]\frac{1}{6} + \frac{4}{3}=\frac{(1)(1) + (4)(2) }{6} =\frac{1+8}{6} =\frac{9}{6} =\frac{3}{2}[/tex]
[tex]\frac{5}{7} + \frac{2}{7}- \frac{1}{14}=\frac{(5)(2) +(2)(2) -(1)(1) }{14} =\frac{10+4-1}{14} =\frac{13}{14}[/tex]
[tex]\frac{5}{6} - \frac{1}{12}+ \frac{4}{12}=\frac{(5)(2) -(1)(1) +(4)(1) }{12} =\frac{10-1+4}{12} =\frac{13}{12}[/tex]
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Verified answer
Explicación paso a paso:
La suma o resta de fracciones es una de las operaciones básicas que permite combinar dos o más fracciones
Resolvamos:
[tex]\frac{2}{3} - \frac{7}{15}=\frac{(2)(5) - (7)(1) }{15} =\frac{10-7}{15} =\frac{3}{15} =\frac{1}{5}[/tex]
[tex]\frac{4}{9} - \frac{1}{3}=\frac{(4)(1) - (1)(3) }{9} =\frac{4-3}{9} =\frac{1}{9}[/tex]
[tex]\frac{1}{6} + \frac{4}{3}=\frac{(1)(1) + (4)(2) }{6} =\frac{1+8}{6} =\frac{9}{6} =\frac{3}{2}[/tex]
[tex]\frac{5}{7} + \frac{2}{7}- \frac{1}{14}=\frac{(5)(2) +(2)(2) -(1)(1) }{14} =\frac{10+4-1}{14} =\frac{13}{14}[/tex]
[tex]\frac{5}{6} - \frac{1}{12}+ \frac{4}{12}=\frac{(5)(2) -(1)(1) +(4)(1) }{12} =\frac{10-1+4}{12} =\frac{13}{12}[/tex]