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a=1, b=-7, c=5
X1²+X2² = (X1+X2)²-2X1.X2
= (-b/a)² - 2.c/a
= (7/1)² - 2.5/1
=49 - 10 = 39
x1 + x2 = -b/a = 7
x1.x2 = c/a = 5
x1² + x2² = (x1 + x2)² - 2x1.x2
= (7)² - 2(5)
= 49 - 10
= 39
no 14
x1 + X2 = 5
X1.X2 = 6
akar persamaan kuadart baru adalah α dan β
α + β = (x1 - 3) + (x2 - 3)
= (x1 + x2) - 6
= 5 - 6
= -1
α.β = (x1 - 3)(x2 - 3)
= x1.x2 - 3x1 - 3 x2 + 9
= x1.x2 - 3(x1 + x2) + 9
= 6 - 3(5) + 9
= 6 - 15 + 9
= 0
persamaan baru
x² - (α + β)x + α.β = 0
x² + x + 0 = 0
x² + x = 0