Question

Diketahui tan A =3/4 dan B= 5/12 (A dan B ) sudut lancip. berapa nilai sin (A+B)


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Answer 1

Verified answer

Jawab

tan A = 3/4
triple pitagoras 3,4,5
sin A = 3/5
cos A = 4/5

tan B = 5/12
triple pitagoras 5,12,13
sin B = 5/13
cos B = 12/13

sin (A+B)= sin A cos B  + cos A sin B
= (3/5)(12/13) + (4/5)(5/13)
= 36/65 + 20/65
= 56/65