Question

Ayuda please cuanto es
[2-(3-7/2)°2]÷(2/7)°-1 = x/1+2°-3

Answer 1

[2-(3-7/2)°2]÷(2/7)°-1 = x/1+2°-3

[2-1•2]: 1- 1= x/1+ 1- 3

0: 1- 1 -1+3= x/1

0-2+3=x/1

1=x/1

X=1•1

X=1

____________

[2-(3-7/2)°2]÷(2/7)°-1 = x/1+2°-3

[2-1•2]:1 -1= 1/1 +1 -3

0:1- 1= 1+1- 3

0-1= 2-3

-1=-1.