Question

11 sampai 15 tolong besok dikumpulin

Answer 1

Verified answer

Jawab

11.
D'hospital
limit (x -> 1)   (4x +1)/.(6x +1) =  (4 +1)/(6+1) = 5/7

12.  limit = 1/3

13.
f'(x)  < 0
x² - 2x - 3 < 0
(x - 3)(x + 1)  <0
x < 3  atau x >1

14. 
m = f'(x)
m = 6x - 4
untuk x = -1 , m = 6(-1) - 4 = -10
y  -y1 = m (x -x1)
y - 3 = -10 (x  +1)
y - 3 = -10x - 10
y = -10x  - 7
10x  + y + 7 = 0

15)

h(x) = 90 x - 3x²
maksimum jika h'(x)= 0
90  - 6x =0
-6x = -90
x= 15
h(15)  = 90(15) - 3(15)²
h(15) = 675
laba = 675.000