Perbandingan Luas ΔHAB
AH = 6√2
AB = r = 6
HB = 6√3
O = Titik Tengah HB dan Tegak Lurus A
AB . AH = AO . HB
6 . 6√2 = AO . 6√3
AO = 36√2 / 6√3
AO = [6√2/√3] × [√3/√3]
AO = 6√6 / 3
AO = 2√6 cm
NB : Jawaban e salah , karena Jarak Ruang ≤ 6√3 cm
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Perbandingan Luas ΔHAB
AH = 6√2
AB = r = 6
HB = 6√3
O = Titik Tengah HB dan Tegak Lurus A
AB . AH = AO . HB
6 . 6√2 = AO . 6√3
AO = 36√2 / 6√3
AO = [6√2/√3] × [√3/√3]
AO = 6√6 / 3
AO = 2√6 cm
NB : Jawaban e salah , karena Jarak Ruang ≤ 6√3 cm
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