dobsz to tak:
pole trapezu HGIJ --> 1/2 * (2 + 3,5) * 1 = 1/2 * 5,5 = 2,25 cm2
pole GJMK --> a*h = 2cm2
pole MKL --> 1/2 * a * h = 1/2 * 2 * 1 = 1 cm2
2+2,25+1=5,25
:)
Odpowiedź:
Pole trapezu GJIH=
[tex]\displaystyle P_{GJIH}=\frac{a+b}{2}\cdot h= \frac{7+4}{2} \cdot2=11\\\text{pole rownelogloboku MKJG}\\P_{MKJG}=a\cdot h=4\cdot 2=8\\\text {pole trojkata MKL}\\P_{MKL}=\frac{1}{2} ah=\frac{1}{2} \cdot 4\cdot 2=4\\P_c=11+8+4=23[/tex]
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dobsz to tak:
pole trapezu HGIJ --> 1/2 * (2 + 3,5) * 1 = 1/2 * 5,5 = 2,25 cm2
pole GJMK --> a*h = 2cm2
pole MKL --> 1/2 * a * h = 1/2 * 2 * 1 = 1 cm2
2+2,25+1=5,25
:)
Odpowiedź:
Pole trapezu GJIH=
[tex]\displaystyle P_{GJIH}=\frac{a+b}{2}\cdot h= \frac{7+4}{2} \cdot2=11\\\text{pole rownelogloboku MKJG}\\P_{MKJG}=a\cdot h=4\cdot 2=8\\\text {pole trojkata MKL}\\P_{MKL}=\frac{1}{2} ah=\frac{1}{2} \cdot 4\cdot 2=4\\P_c=11+8+4=23[/tex]