Question

100 ml larutan naoh memiliki ph 13. berapa gram naoh dalam larutan tersebut?

Answer 1

Ph = 13; pOH = 1

[OH⁻] = 10⁻¹

[OH⁻] = M/(mr.v)
10⁻¹ = M/(40.0,1)
10⁻¹ . 4 = M
0,4 gr = M

^_^

Answer 2

OH- = 10^-1
[NaOH] = 0,1 M
M = GRAM/MR  x 1000/100
0,1 = GRAM/40 x 1000/100
4 = GRAM x 10
GRAM = 4/10
GRAM = 0,4 gram