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= [ ( 0,01 × 100) + ( 0,01 × 100 × 2)] ÷ ( 100 + 100)
= 0,015
OH^- = M campuran = 1,5 × 10^-2
pOH = 2 - log 1,5 ⇒ pH = 12 - log 1,5.