Jawaban:
∠ADB + ∠BDC = Berpelurus
(2x + 5°) + 57° = 180°
2x + 5° + 57° = 180°
2x + 62° = 180°
2x = 180° - 62°
2x = 180° 118°
x = 118°/2
x = 59°
∠AOB + ∠BOC = Berpenyiku
3x - 2° + 2x + 7° = 90°
3x + 2x + 7° - 2° = 90°
5x + 5° = 90°
5x = 90° - 5°
5x = 85°
x = 85°/5
x = 17°
'비상' (Svt)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Jawaban:
Gambar 1.
∠ADB + ∠BDC = Berpelurus
(2x + 5°) + 57° = 180°
2x + 5° + 57° = 180°
2x + 62° = 180°
2x = 180° - 62°
2x = 180° 118°
x = 118°/2
x = 59°
Gambar 2.
∠AOB + ∠BOC = Berpenyiku
3x - 2° + 2x + 7° = 90°
3x + 2x + 7° - 2° = 90°
5x + 5° = 90°
5x = 90° - 5°
5x = 85°
x = 85°/5
x = 17°
'비상' (Svt)