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[(y/x)²-1] dx + y/x dy = 0
y = ux
dy = u dx + x du.........subtitusi ke pers. awal
[(u)²-1] dx + u(u dx + x du) = 0
2u²-1 dx + ux du = 0 ; bagi x.(2u²-1)
1/x dx + u/(2u²-1) du = 0
ln x + (1/4).ln (2u²-1) = ln c₁
ln x + (1/4).ln (2(y/x)²-1) = ln c₁
ln (x/4)(2(y/x)²-1) = ln c₁
ln ((y²/2x)-(x/4)) = ln c₁
(y²/2x)-(x/4) = c₁
y²/2x = 2c₁ + (x/2)
y² = 2c₁.x + x²/2
y = √(2c₁.x + x²/2)