Respuesta:
[tex]Y-5=3Y-25\quad :\quad Y=10\\\\x-\left(2x+1\right)=8-\left(3x+3\right)\quad :\quad x=3[/tex]
Explicación paso a paso:
[tex]Y-5=3Y-25\\Y-5+5=3Y-25+5\\Y=3Y-20\\Y-3Y=3Y-20-3Y\\-2Y=-20\\\frac{-2Y}{-2}=\frac{-20}{-2}\\Y=10[/tex][tex]x-\left(2x+1\right)=8-\left(3x+3\right)\\x-\left(2x+1\right)=8-\left(3x+3\right)\\-x-1=-3x+5\\-x-1+1=-3x+5+1\\-x=-3x+6\\-x+3x=-3x+6+3x\\2x=6\\\frac{2x}{2}=\frac{6}{2}\\x=3[/tex]
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Respuesta:
[tex]Y-5=3Y-25\quad :\quad Y=10\\\\x-\left(2x+1\right)=8-\left(3x+3\right)\quad :\quad x=3[/tex]
Explicación paso a paso:
[tex]Y-5=3Y-25\\Y-5+5=3Y-25+5\\Y=3Y-20\\Y-3Y=3Y-20-3Y\\-2Y=-20\\\frac{-2Y}{-2}=\frac{-20}{-2}\\Y=10[/tex][tex]x-\left(2x+1\right)=8-\left(3x+3\right)\\x-\left(2x+1\right)=8-\left(3x+3\right)\\-x-1=-3x+5\\-x-1+1=-3x+5+1\\-x=-3x+6\\-x+3x=-3x+6+3x\\2x=6\\\frac{2x}{2}=\frac{6}{2}\\x=3[/tex]