Question

1. X6 y9 : (x4 y2 z5 : - x2 y4 z3)

2.16x6 y8 : (4x3 y2 * 2x2 y4)

itu perpangkatan yang belakang
yang x = x
* = kali

tolong bantu pake caranya yaa

Answer 1

1. x^6 . y^9 : (x^4 . y^2 . z^5 : -x^2 . y^4 . z^3)
= x^6 . y^9 : (-x^2 . y^-2 . z^2)
= -x^4 . y^11 . z^-2

2. 16 x^6 . y^8 : (4 x^3  y^2 * 2 x^2 y^4)
= 16 x^6 . y^8 : (8 x^5 . y^6)
= 2xy^2