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20g HF = 100%
1g H = 5%
2.
Cu2O
144g Cu2O = 100%
16g O = 11,1%
X2O
(2x+16)g X2O = 100%
x g X = 11,1%
22,2x + 177,6 = 100x
77,8x = 177,6
x = 2g : 2 => 1g=> wodór
H2O