Question

1. Tentukan sumbu simetri dari fungsi kuadrat
y = 2x² - 7x - 4

2. Tentukan titik puncak dari fungsi kuadrat
y = x² - 2x - 24
​

Answer 1

Fungsi Kuadrat

[Verteks dan Sumbu Simetri]

..

[tex]x_{p}= \frac{ - b}{2a} [/tex]

[tex]y_{p} = - \frac{b {}^{2} - 4ac }{4a} [/tex]

[tex]Verteks \: (x. \: y) = (x_{p}. \: y_{p})[/tex]

..

Nomor 1

[tex]x_{p}= \frac{ - b}{2a} [/tex]

[tex]~~~~~= \frac{7}{4} [/tex]

..

Nomor 2

[tex]x_{p}= \frac{ - b}{2a} [/tex]

[tex]~~~~~= \frac{2}{2} [/tex]

[tex]~~~~~= 1[/tex]

..

[tex]y_{p} =- \frac{b {}^{2} - 4ac }{4a} [/tex]

[tex]~~~~~= - \frac{( - 2) {}^{2} - 4(1)( - 24) }{4(1)} [/tex]

[tex]~~~~~= - \frac{4 + 96}{4} [/tex]

[tex]~~~~~=- \frac{100}{4} [/tex]

[tex]~~~~~=- 25[/tex]

..

[tex]Verteks \: (x. \: y) = (1. \: -25)[/tex]

..

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[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at}}\boxed{\colorbox{ccddff}{14/03/23}}[/tex]