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r = diameter/2
r = 24/2
r = 12 cm
Cari luas permukaan
LP = 4 × π × r²
LP = 4 × 3,14 × 12²
LP = 4 × 3,14 × 144
LP = 1.808,64 cm²
Nomor 2 adalah tabung
r = d/2
r = 12/2
r = 6 cm
cari tinggi dengan pythagoras
t = √(15²-12²)
t = √(225-144)
t = √81
t = 9 cm
cari volume tabung
V = π × r × r × t
V = 3,14 × 6 × 6 × 9
V = 1.017,36 cm³
r= 24/2 = 12 cm
volume = 4/3 πr³
=4/3 x 3,14 x 12³
=4/3 x 3,14 x 1728
=4 x 3,14 x 576
=7234,56 cm³
luas permukaan = 4 πr²
=4 x 3,14 x 12²
=1808,64 cm²
yg tabung aku lupa caranya, maaf yaa...