Jika sin A= 3/5 dan cos B= 5/13 untuk sudut A dan B lancip, maka tan A - tan B/ 1 + tan A tan B = ...
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TanA = 3/4 tanB= 12/5 = tanA-tanB / 1+(tanA.tanB) = (3/4-12/5 )/ 1+ (3/4*12/5) = (-33/20) / (56/20) = -33/56
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