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273++25=298K
25°C=298K
2. dik. e=0,7; r=5cm=5*10⁻²; T=70°C+273=343K; σ=5,67*10⁻⁸w/m²K
dit. Q??
jb.
A=πr²= 3,14*(5*10⁻²m)²=78,5*10⁻⁴m₂
σtT⁴A
Q=0,7*5,67* 10⁻8 w/ m² K⁴ *(78,5* 10⁻⁴m²) *( 343K)⁴ *180s
Q = 77,6J