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tK = tc + 273
tC/5 = (tF - 32)/9
1)42°F
tC = 5(42 - 32)/9
tC = 5,56°C
2)
- 210°C
a)
tK = - 210 + 273
tK = 63 K
b)
- 210(9/5) = tF - 32
tF = - 346°F
3)
203°F
tC = 5/9(203 - 32)
tC = 95°C