Question

1. perhatikan gambar segitiga diatas
Nilai x adalah...

2. nilai x yang memenuhi sistem persamaan 8x - 3y = -4 dan 6x + y = 10 adalah ....



tolong cara nya

​

Answer 1

Verified answer

Nomor 1

[tex]\begin{aligned}\sf x &= \sf \sqrt{10^2 - 6^2} \\ &= \sf \sqrt{100 - 36} \\ &= \sf \sqrt{64} \\ &= \sf 8 \ cm\end{aligned}[/tex]

 

Nomor 2

[tex]\begin{cases} \sf 8x - 3y = -4 \dots (1) \\ \sf 6x + y = 10 \Rightarrow y = 10 - 6x\dots (2)\end{cases}[/tex]

•› Substitusi y

[tex]\begin{aligned}\sf 8x - 3y &= \sf -4 \\ \sf 8x - 3(10 - 6x) &= \sf -4 \\ \sf 8x - 30 + 18x &= \sf -4 \\ \sf 8x + 18x &= \sf -4 + 30 \\ \sf 26x &= \sf 26 \\ \sf x &= \sf \frac{26}{26} \\ \sf x &= \sf 1 \end{aligned}[/tex]

•› Substitusi x

[tex]\begin{aligned}\sf y &= \sf 10 - 6x \\ \sf y &= \sf 10 - 6(1) \\ \sf y &= \sf 10 - 6 \\ \sf y &= \sf 4\end{aligned}[/tex]

⌗SDaze ⋆࿐໋₊

Answer 2

بِسْـــــــمِ اللّٰهِ الرَّحْمٰنِ الرَّحِيْمِ

Nomor 1

x = √(10² - 6²)

x = √(100 - 36)

x = √64

x = 8 m

Nomor 2

8x - 3y = -4.... (1)

6x + y = 10.... (2)

•› Eliminasi nilai y

8x - 3y = -4 |×1 | 8x - 3y = -4

6x + y = 10 |×3| 18x + 3y = 30

___________ +

26x = 26

x = 26 ÷ 26

x = 1

وَاللّٰهُ اَعْلَمُ بِاالصَّوَافَ