1. Oblicz stosunek wagowy pierwiastków w związkach: N₂O₃ FeCl₂
2.Oblicz skład procentowy pierwiastków w H₂O AlCl₃
1.
N2O3
mN : mO = 28 : 48 = 7 : 12
FeCl3
mFe : mCl = 56 : 72 = 7 : 9
2.
M (H2O)=2+16=18 g/mol
%H=2g/mol*100%:18g/mol=11,11%
%O=100-11,11=88,89 %
M (AlCl3)=27+106,5=133,5 g/mol
%Al=27g/mol*100%:133,5g/mol=20,22 %
%Cl=100-20,22=79,78 %
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1.
N2O3
mN : mO = 28 : 48 = 7 : 12
FeCl3
mFe : mCl = 56 : 72 = 7 : 9
2.
M (H2O)=2+16=18 g/mol
%H=2g/mol*100%:18g/mol=11,11%
%O=100-11,11=88,89 %
M (AlCl3)=27+106,5=133,5 g/mol
%Al=27g/mol*100%:133,5g/mol=20,22 %
%Cl=100-20,22=79,78 %