1) Oblicz stosunek masowy pierwiastków w: Na2SO4, C2H5OH. HCOOH
Na₂SO₄= 2*23u +32u+4*16u=46u+32u+64u=142u
C₂H₅OH. = 2*12u+3*1u+16u+1u=24u+3u+16u+1u=44u
HCOOH = 2u+12u+32u=46u
Pozdrawiam
M:)
1. Na2SO4
2* mNa:1*mS:4*mO
2*23u:1*32:4*16u
46u:32u:64u
23:16:32
2.C2H50H
2*mC:5*mH:1*mO:1*mH
2*12u:5*1u:1*16u:1*1u
24u:5u:16u:1u
3.HCOOH
1*mH:1*mC:1*mO:1*mO:1*mH
1*1u:1*12u:1*16u:1*16u:1*1u
1:12:16:16:1
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Na₂SO₄= 2*23u +32u+4*16u=46u+32u+64u=142u
C₂H₅OH. = 2*12u+3*1u+16u+1u=24u+3u+16u+1u=44u
HCOOH = 2u+12u+32u=46u
Pozdrawiam
M:)
1. Na2SO4
2* mNa:1*mS:4*mO
2*23u:1*32:4*16u
46u:32u:64u
23:16:32
2.C2H50H
2*mC:5*mH:1*mO:1*mH
2*12u:5*1u:1*16u:1*1u
24u:5u:16u:1u
3.HCOOH
1*mH:1*mC:1*mO:1*mO:1*mH
1*1u:1*12u:1*16u:1*16u:1*1u
1:12:16:16:1