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%Al=54/102*100%=53%
%o=48/102*100%=47%
Al:O
54:48
27:24
9:8
al-27u O- 16u
m Al= 54u m O= 48u
stosunek 54:48 -> 27:24 -> 9:8
skład %
Al 54/102*100%= 53%
O 100%- 53%=47%
2) 2 Al + 3 S → Al2S3