1. Oblicz stezenie jonów [H+] i [OH-] jeżeli:
a) pH=0
b) pH=4
c)pH= 10
2. Ile wynosi wartość pH, jezeli stezenie jonów [OH-] jest równe:
a) 10 do -5 ( w potędze )
b) 10 do -14 ( w potędze )
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1)
założenie V=1dm³
a)
pH=0
[H⁺]=10⁰=1mol/dm³
pOH=14
[OH⁻]=14-1=13mol/dm³
b)
pH=4
[H⁺]=10⁻⁴mol/dm³
pOH=14-4=10
[OH⁻]=10⁻¹⁰mol/dm³
c)
pH=10
[H⁺]=10⁻¹⁰mol/dm³
pOH=14-10=4
[OH⁻]=10⁻⁴mol/dm³
2)
a)
[OH⁻]=10⁻⁵
pOH=-log[10⁻⁵]
pOH=5
pH=14-pOH
pH=14-5=9
pH=9
b)
[OH⁻]=10⁻¹⁴
pOH=14
pH=14-pOH
pH=14-14=0
pH=0
Pozdrawiam :)