1)
mCH3OH=12u+4u+16u=32u
%C = (12/32)*100% = 37,5%
%C = (4/32)*100% = 12,5%
%C = (16/32)*100% = 50%
2)
3C3H5(OH)3
9 at. węgla
24 at. wodoru
9 at. tlenu
-----------------
Suma: 42 atomy
3)
2Zn + O2 ---> 2ZnO
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1)
mCH3OH=12u+4u+16u=32u
%C = (12/32)*100% = 37,5%
%C = (4/32)*100% = 12,5%
%C = (16/32)*100% = 50%
2)
3C3H5(OH)3
9 at. węgla
24 at. wodoru
9 at. tlenu
-----------------
Suma: 42 atomy
3)
2Zn + O2 ---> 2ZnO