1 oblicz mase substancji z 500g roztworu 5 %
2 ile soli i ile wody potrzeba na przygotowanie 250g roztworu 2%
1 500g=100% x=5% 500*5/100=25g
250g=100% x=2% 250*2/100=5g-masa soli 250-5=245g-masa wody
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1 500g=100% x=5% 500*5/100=25g
250g=100% x=2% 250*2/100=5g-masa soli 250-5=245g-masa wody