3n, 3n+3, 3n+6 - trzy kolejne liczby naturalne podzielne przez 3
3n+3n+3+3n+6= 9n + 9 = 9(n+1) i n+1∈N
c.k.d.
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3n, 3n+3, 3n+6 - trzy kolejne liczby naturalne podzielne przez 3
3n+3n+3+3n+6= 9n + 9 = 9(n+1) i n+1∈N
c.k.d.