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HCL
0,5= gr / 18
gr = 18×0,5 = 9
gr CH3COOH = 60×0,2 =12
Molalitas :
Gr hcl/ Mr x 1000/gr cuka (pelarut )
9/18 x1000/12
=0,5x8.3=41.6 molal
Fraksi mol terlarut : 0.5/0.2+0.5=0.7
Fraksi mol pelarut : 0.2/0.5+0.2=0.2
m