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f (x) = x² – 4x + 3
f'(x) = 2x - 4
2x = 4
x = 4/2 = 2
f(2) = 2² - 4(2) + 3 = 7 - 8 = 1
koordinat titik minimum = { 2, 1 }
2)
y = x² – 8x + 12
y = x – 2
<=> x² - 8x + 12 = x - 2
x² - 9x + 14 = 0
(x - 2)(x - 7) = 0
x1 = 2
x2 = 7
titik grafiknya :
(2, 0) dan (7, 0)
f'(x) = 2x - 4
2x = 4
x = 4/2
= 2
f(2) = 2² - 4(2) + 3
= 7 - 8
= 1
titik minimum = 2, 1
y = x² – 8x + 12
y = x – 2
x² - 8x + 12 = x - 2
x² - 9x + 14 = 0
(x - 2)(x - 7) = 0
x1 = 2
x2 = 7
titik grafiknya :
(2, 0) dan (7, 0)