1. Kawat sepanjang 2m dibuat sebuah kerangka balok ukuran 20cm x 18cm x t cm maka nilai t adalah
2. Sebuah bak air panjangnya 20 dm, lebar 15dm, tinggi 10dm bila bak diisi penuh, maka volume bak adalah....m3
3. Ukuran panjang dan lebar balok berturut turut 12cm dan 9cm. Jika panjang salah satu diagonal ruang 17cm maka volume balok mohon bantuannya pake cara, makasih yg udh kasih tau
liwonsubagyo
1) 2m = 200 cm Panjang rusuk = 4 ( p + l + t ) 200 = 4 ( 20 + 18 + t ) 20 + 18 + t = 200 : 4 38 + t = 50 t = 50 - 38 = 12 cm Jadi nilai t = 12cm 2) V = p x l x t = 20 x 15 x 10 = 3.000cm³ 3) Diagonal ruang = √ p² + l² + t² 17 = √ 12² + 9² + t² t = √ 17² - 225 = √ 289 - 225 = √ 64 = 8cm V = p x l x t = 12 x 9 x 8 = 864cm³
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Alfatta
1) 2m = 200 cm Panjang rusuk = 4 ( p + l + t ) 200 = 4 ( 20 + 18 + t ) 20 + 18 + t = 200 : 4 38 + t = 50 t = 50 - 38 t = 12 cm 2) V = p x l x t = 20 x 15 x 10 = 3.000cm³ 3) Diagonal ruang = √ p² + l² + t² 17 = √ 12² + 9² + t² t = √ 17² - 225 = √ 289 - 225 = √ 64 = 8cm V = p x l x t = 12 x 9 x 8 = 864cm³
Panjang rusuk = 4 ( p + l + t )
200 = 4 ( 20 + 18 + t )
20 + 18 + t = 200 : 4
38 + t = 50
t = 50 - 38
= 12 cm
Jadi nilai t = 12cm
2) V = p x l x t
= 20 x 15 x 10
= 3.000cm³
3) Diagonal ruang = √ p² + l² + t²
17 = √ 12² + 9² + t²
t = √ 17² - 225
= √ 289 - 225
= √ 64
= 8cm
V = p x l x t
= 12 x 9 x 8
= 864cm³
Panjang rusuk = 4 ( p + l + t )
200 = 4 ( 20 + 18 + t )
20 + 18 + t = 200 : 4
38 + t = 50
t = 50 - 38
t = 12 cm
2) V = p x l x t
= 20 x 15 x 10
= 3.000cm³
3) Diagonal ruang = √ p² + l² + t²
17 = √ 12² + 9² + t²
t = √ 17² - 225
= √ 289 - 225
= √ 64
= 8cm
V = p x l x t
= 12 x 9 x 8
= 864cm³