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= 4. 3.14. 216/3
= 2712,96/3
= 904,32 cm²
2.luas permukaan kerucut
dicari panjang selimut ny dulu
s²= r²+t²
= 3²+4²
= 9+16
= 25=√25= 5
maka luas permukaan kerucut
= πr(s+r)
= 3,14 . 5. (5+3)
= 15,70(8)
= 125,6 cm²
3. luas permukaan tabung
= 2πr(r+t)
= 2. 22/7 . 7.(7+4)
= 44(21)
= 924 cm²