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f⁻¹(x) = ?
f(x)= y
x²- 2x + 3 = y
x = y- x² - 3
-------------
-2
x = -x²+y-3 - ( -x²+y - 3) x²-y+3
------------ = ---------------------- = -------------
-2 - (-2) 2
x²-x+3
jadi f⁻¹(x) = ----------
2
semoga bermanfaat y
mav y kalo salah :)
y - 2 = x² - 2x + 3 -2
y - 2 = x² - 2x + 1
y - 2 =