Question

1. jika 3 log 2 = a dan 2 log 7 = b maka 28 log 147 =

Answer 1

28'log 147
= 2'log 147 / 2'log 28
= 2'log (7² × 3) / 2'log (2² × 7)
= (2'log 7² + 2'log 3) / (2'log 2² + 2'log 7)
= (2 b + (1/a)) / (2 + b)
= (2ab + 1) / (2a + ab)