1. Ile gramów (i ile moli) wodorotlenku sodu znajduje sie w 250 gramach roztworu o stężeniu procentowym równym 15%
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ms = 15/100 * 250
ms = 37,5 g
M (NaOH) = 40 g/mol
n= m/M
n = 37,5/ 40
n = 0, 94 mola
n = około 1mola