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n = 3 ion, α = 0,75, i = 1 + (3-1)(0,75) = 2,5
ΔTb = [massa zat/Mr] x [1000/massa air] x Kb x i
102,6 - 100 = [g/74] x [1000/250] x 0,52 x 2,5
2,6 = [g/74] x 5,2
g/74 = 0,5
diperoleh massa Ca(OH)₂ yaitu g = 37