Materi : Bentuk dan Persamaan Kuadrat
y = x² - 3
Titik potong sumbu - y [ x = 0 ]
y = 0² - 3
y = 0 - 3
[ y = -3 ] => ( 0,-3 )
3 satuan ke bawah [ -3 ]
[ x¹ = 3 dan y¹ = 4 ]
______________/
( x - x¹ )( x - x² ) = 0
( x - 3 )( x - 4 ) = 0
x² - 7x + 12 = 0
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Verified answer
Materi : Bentuk dan Persamaan Kuadrat
Soal Nomor 1
y = x² - 3
Titik potong sumbu - y [ x = 0 ]
y = 0² - 3
y = 0 - 3
[ y = -3 ] => ( 0,-3 )
Soal Nomor 2
3 satuan ke bawah [ -3 ]
Soal Nomor 3
[ x¹ = 3 dan y¹ = 4 ]
______________/
( x - x¹ )( x - x² ) = 0
( x - 3 )( x - 4 ) = 0
x² - 7x + 12 = 0
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]