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f(3)=2*3+m=4
6+m=4
m=4-6
m=(-2)
2.A f0=0*a+m=-6
m=(-6)
f3=3*a+(-6)=-5
3a=-5+6
a=1/3
m=-6 dan a=1/3
B f2=(2a+m=3) - f4=(4a+m=4)
(2a=3) -(4a=4)
-2a=-1
a=1/2
a=1/2 => f2=2*1/2+m=3
1+m=3
m=2
1. m=2
2. a=1/2 dan m= 2